b^2-19b+48=

Solution for b^2-19b+48= equation:

Simplifying
b2 + -19b + 48 = 0

Reorder the terms:
48 + -19b + b2 = 0

Solving
48 + -19b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(3 + -1b)(16 + -1b) = 0

Subproblem 1
Set the factor '(3 + -1b)' equal to zero and attempt to solve:

Simplifying
3 + -1b = 0

Solving
3 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = 0 + -3
-1b = 0 + -3

Combine like terms: 0 + -3 = -3
-1b = -3

Divide each side by '-1'.
b = 3

Simplifying
b = 3
Subproblem 2
Set the factor '(16 + -1b)' equal to zero and attempt to solve:

Simplifying
16 + -1b = 0

Solving
16 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -1b = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -1b = 0 + -16
-1b = 0 + -16

Combine like terms: 0 + -16 = -16
-1b = -16

Divide each side by '-1'.
b = 16

Simplifying
b = 16
Solution
b = {3, 16}